Fernando_4

I'm not sure what you're trying to do... here's a [JSBin](http://jsbin.com/vazit/2/edit) with what you posted and it is creating output, I just don't have any idea what you're grabbing and what result is expected. Maybe some more code would help. Even elaborating on that jsbin would be great^^

You set `type: "POST"` but you're sending `data:"cart_itemid="+cart_itemid+"&cart_qty="+cart_qty` as if it were `"GET"` try replacing the `type` or changing how data is sent. On another note, if you're already using jQuery, take a look at `.post()` in the documentation for a shortand ajax post request with callbacks.

I don't know laravel, but I think I would need to take a look at the method `save()` in the `question` class to see what it's doing with those values. Although, since you are in a loop, saving one item should lead to saving another. You might also want to …

<form method="POST" action="OnlineOrders.php"> <table border=0> <tr> ............... </tr> </table> <br /> <input name="submit" type="submit" value="Submit Order" /> <input type="reset" name="reset" value="Recalculate Order" /> </form> <hr /> Keep in mind all inputs, even the buttons, have to stay in the form you want to submit. Your `OnlineOrders.php` will collect the forms …

I think you want it to be something like this: function House (w, d, a) { //i trimmed down the passed variables for clarity as to what goes where this.windows = w; this.doors = d; this.attic = a; } //create an instance of House passing in the variables var myHouse …

I think you want to use the contents of 'admin/addBlogs' script within the 'user/blogger' script before content is published to the user. The problem I see is, once a php script finishes execution and sends output to the user the only way to run another php script would be through …

Here's how I'm thinking about inserting values into two tables. Each `reservation` will have a set of `services` the amount of which can vary, so I need to setup the query dynamically, here's my first sketch, although not tested yet. function saveBooking($fullBook) { $mysqli = new mysqli(HOST, USER, PASSWORD, DB_PRICE); …

You forgot to add `display:block;` to the elements you need to rotate.

I'm guessing it has to do with the [array_pointer](http://www.php.net/manual/en/function.reset.php) keep in mind they don't recommend `reset` on associative arrays, but it might give you an idea. **Edit** Take a peek at the resulting jQuery function to see if the problem comes from PhP or if it's jQuery we have to …

It will always say "All Assets Deleted", because on line 6 you didn't say it's an `else` block. As for the condition itself, it seems you might want to take a look at [affected_rows](http://us1.php.net/manual/en/mysqli.affected-rows.php).

Not knowing exactly what you're struggling with and for the looks of it, you're getting stuck right at the beggining I would suggest [Google Forms](http://www.google.com/google-d-s/createforms.html). It might just give you all you need. Give us more information if all this doesn't work for you.

I'm not sure how `simple_html_dom.php` works and if it can read classes/ids so you could do something like `$html->find('p id=links')` or `$html->find('p #links')`. Can you post the `find()` function from that class so we can try to figure it out? If it's something you grabbed from someone on the web …

Try making a file in the `users` folder that will select the right file. I'm assuming you're detecting `username` from a post variable. So `users/users.php` would have something like this: if(isset($_POST['username']) && $_POST['username'] != ''){ //include "users/username/profile.php" include_once('users/'.$_POST['username'].'/profile.php'); } You'll want to add testing if the file exists before including …

So basically you want to populate a second `select` based on what was selected on the one you posted, correct? We need a bit more info if that's the case. 1. Do you want to do this after a reload? The user selects a manufacturer and posts the form in …

1. The `mysql` API to connect to the database is [deprecated as of php5.5](http://www.php.net/manual/en/intro.mysql.php), try looking into [msqli](http://pt2.php.net/mysqli) or [pdo](http://www.php.net/manual/en/book.pdo.php) 2. `mysql_real_escape_string` [deprecated as of php5.5](http://pt2.php.net/mysql_real_escape_string) 3. Carefull with [sql injection](http://www.php.net/manual/en/security.database.sql-injection.php). Try looking at [prepared statements](http://www.php.net/manual/en/mysqli.quickstart.prepared-statements.php) 4. If you're concatenating strings to build your query you should change this: line …

From what I can see you would need to test `$_POST['soptns']` value to output the correct file. Something like this on the same file, since the form action is itself: switch($_POST['soptns']){ case 'NS': include_once(normalSale.php); break; case 'PT': include_once(platinumSale.php); break; case 'SP': include_once(seniorsSale.php); break; case 'UP': include_once(upgrade.php); break; default: include_once(default.php); break; …

EXLPLAIN SELECT customer.custid, customer.compname, customer.phone, customer.depot, acctofficer.acctfullname AS acctoff, STR_TO_DATE(mastorders.lastsuppdate,'%d-%m-%Y') AS purchdate, STR_TO_DATE(transactions.timestamp,'%Y-%m-%d') AS debtage, format( customer.balance, 2) AS balance, customer.balance AS balance1 FROM customer, mastorders, acctofficer, transactions WHERE customer.custid = mastorders.custid AND acctofficer.acctoffid = customer.acctoff AND customer.depot = '$depot' GROUP by customer.id ASC Go into your database manager (phpMyAdmin …

With the following bit of code I'm trying to get the key's of each sub-array that I will need at this part of the script. It's working so I'm not too worried about this, I just think there should be a pre-built function to do the same thing. foreach($myArray['ico'] as …

I believe you're looking for websockets, however I haven't got a clue how it works, or how to implement it. I just read about it the other day and never tried it out. Try starting [here](http://en.wikipedia.org/wiki/WebSocket), after that I'm not the best person to point you in any direction on …

I've never tried to pull that off, but I would think to start looking [here](https://developers.google.com/maps/web/). Eventually you'll find a term that repeats itself and you're ready to google what you actually need. Sorry for not helping more, but I've never done it, so I don't really know where the info …

Before the loop try to see what you're actually getting from the database with this: echo '<pre>'; var_dump($resultSet); echo '</pre>'; In the loop you can try this to see what each `$i` block is giving you: echo '<pre>'; var_dump($resultSet[$i]); echo '</pre>'; If that doesn't show you the problem, try posting …

Usually it has to do with whitespace before `<?php` or after `?>`. Sometimes it has to do with `session_start();` being called twice, normally in diferent files. If that's the case then you need to test `if(!headers_sent())` and put your `session_start();` in there. There is a fix for it if it's …

Hi all, I've made a query that gathers info from several tables, after it was working, there was the need to integrate yet another table, however I can't seem to put it to work. I've seen some of this "witchcraft" before, but can't seem to find a tutorial, basically because …

Wow, you gotta work on indentation... it's a pain to read through this. I'm going to repost the query with indentation and code high-lighting for the next guy. At this point I'm still not sure I can help though... QUERY: SELECT DISTINCT customer.custid, customer.compname, customer.balance AS balance, customer.phone, acctofficer.acctfullname AS …

There are a few options here. /* BEFORE PAGE IS SENT */ 1. When the page loads, grab the array you need from the database and pass it along to javascript with `json_encode()`. /* AFTER PAGE IS SENT */ 2. Use AJAX's asynchronous xhr to a file that grabs that …

Try [this](http://www.apachefriends.org/faq_windows.html) > The easiest way is to use the security console, which you can access at http://localhost/security/ This console creates a password for the MySQL user root and adjusts the phpMyAdmin configuration. > Another approach is to configure it with the "XAMPP Shell" (command prompt). Open the shell and …

**On line 3**: You define ['current_language'] as 'fr' and never change it, so it will always be 'fr'. **On line 15**: This is personal preference, I wouldn't create a link to a language that is translated. English would always be English and never Anglais, since when the website opens I …

Is the error message saying headers are sent on line `header ('location: user/dashboard.php');` or is the error being thrown from `dashboard.php`? Usually I get that error when I `session_start();` on the target file. If that is the case, you're probably calling `session_start();` on both files and since there might be …