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When i run this php file it syas that image cannot be displayed because it contains error.plz help me to solve this problem <?php $query=mysql_connect("localhost","root","root"); mysql_select_db("freeze_demo",$query);include('phpgraphlib.php'); $graph = new PHPGraphLib(400,300); $data_array=array(); $query1="SELECT name,age FROM addd WHERE name='pavi' "; $query2 = mysql_query($query1) or die('Query failed: ' . mysql_error()); if ($query2) { …
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