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[QUOTE=mkohnlein17;436129]Address/////////Contents 08A//////////////010FA210FB 08B//////////////010FA0F08D 08C//////////////020FA210FB Here is a simple way to understand this problem: Contents are divided up into two 5 bit instructions, LH and RH LH instruction = 010FA opcode = 01 address = 0FA RH instruction = 210FB opcode = 21 address = 0FB Since this is in hexadecimal …

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