jrdark13

Can we get some new updated sticky of newer books. C++ standards have changed a lot since most of these books were published (2004~5). Specially if we are talking about windows based software. Some of the two good ones I found are: Ivor Horton's Beginning Visual C++ (2010) [can be …

[QUOTE=paulthom12345;784753]Well im voting for the scanner. Thats how i learnt and thats how i go, i dont find anything wrong with it so i stay that way.. addmitedly i really dont know a thing about Buffered Reader anyway, so it could be loads better for all i know.[/QUOTE] Ditto... If …

You would get more help if you wrote a proper title when creating a thread.

I'm am in real need of the diskpart.cpp file and it's dependents from Windows CE 6.0 I don't have the time or requirements to download and install everything for Windows CE. It would be greatly appreciated.

Assuming your on Windows... Wouldn't a batch file be sufficient? Something along the lines of ... [CODE]netsh interface ip set address name="Local Area Connection" static 192.168.0.100 255.255.255.0 192.168.0.1 1[/CODE] If not you could "cheat" and do a ShellExec() I'm assuming anything deeper than that you would have to work with …

Good job, not going to test it but it gave me an idea and I might even scrape some code from it to mine. I already have the ajax portion I'm just going to add the idea of a ajaxhint.php and onkeyup. Any idea of how to get it to …

Here is a little something I use, It's rough and could be greatly improved but it works. One problem I notice is that the new div is created inside the previous so it keeps getting bigger and pushes everything below it down. That div is needed because or else the …

you can do... [CODE] //declare which layers you want. //if one layer is not declared then no problem cause it will not be added. $Layer1="Layer1".","; $Layer2="Layer2".","; $Layer3="Layer3".","; //compile to one variable and get rid of ending comma. $query = substr($Layer1.$Layer2.$Layer3,0,-1); [/CODE] does that work for you?

have you tried to echo $scheck to see what it contains if($check) all it means is that the variable holds contents and looking at your code I don't see where you just declare the variable. I see you add to it by $scheck [B].=[/B] .... but never a $scheck [B]=[/B] …

The code below I have a problem... When you hit enter on a text field firefox stays at the same page because I have returned false; (I assume) but IE still submits the form normally. What am I doing wrong? [CODE=javascript] window.onload = function() { var form = document.getElementById('keyword'); var …

I think this is more of a styling question. My suggestion is to set DIVs around each data (name, last name and image) then using CSS set the width and height to be all the same then float:left. something like this: [code=css] div.display{ background-color:#161616; text-align:center; float:left; width:190px; margin:10px 4px; height:200px; …

There is a "table" started already and I think it doesn't belong... [CODE=php] // if everything successful create query // this selects all rows where the type is the one you chose in the dropdown // * means that it will select all columns, ie name and type as i …

check this tutorial out, It just helped me with the same problem... [url]http://www.deitel.com/articles/java_tutorials/20060408/Arithmetic_InputMismatch_Exceptions/[/url]

try your query as: [code] $sql_query = "SELECT * FROM base_data WHERE type='".$chooser."'";[/code] notice $chooser has been properly removed from the leteral sentence.

I assume the drowpdown/layer menu is javascript simply because it has to wait until the entire page is loaded so that I can see the sub-options... I really wouldn't want it to be redone but sometimes at work I have slow internet and loading the page just pisses me off …

If i can try to figure out this correctly, you have to have both permissions from the current server AND the remote server. One should be allowed to retrieve from another server and the other to accept and send to remote server but I'm not sure.

I don't know about the other stuff but I know for a fact your second code didn't work be cause [inlinecode]if ($urlres = true) {[/inlinecode] should be [inlinecode]if ($urlres == true) {[/inlinecode] instead. Oh, and why are you using #?

This is my assignment, before some of you complain, I finished it. It works all I want is something that is in the back of my head bugging me. If a user was to input a letter instead of a number how do I keep the program from crashing and …

I'm not entirely sure but wouldn't [inlinecode]if(mysql_query($pullprofile,$con))[/inlinecode] return true only if the query was accepted not if there was a row result?. That means that your query is generating an error probably due to the fact that you are requesting literally $idnum, use {$idnum} to make sure it goes through …

Here it is man hopefully fixed but remember... 1. When you call for a column its ` key not ' . (Its the key right below ESC, i don't remember the character name) 2. When calling static data it's ' (single quote) 3. table names don't have to be quoted. …

Entering your php file directory into a Download manager will not download your php data only what the php file generates or "source". You don't have to worry about that. It's like people right clicking and selecting "View Source" on your browser, that is all they'll see. For security reasons …

the wild card I think your looking for is % within the MySQL command. so in the phrase "blue house" so... "%house" = TRUE; "blue%" = TRUE; "%blue" = FALSE; "house%" = FALSE; "%blue%" = TRUE; "%house%" = TRUE; example mysql command: [CODE] SELECT * FROM `table` WHERE `col` LIKE …

I think you really have to at least attempt to do your homework not just ask people how to start. First of all try to figure out the [COLOR="Red"]logic[/COLOR] of it and write it out in pseudocode(words) before even starting. Then give us what you've got cause up there you …

You'll need javascript not php.

Like what I think is stated above, you probably want to go by upload first meaning [CODE] //Before should be all other variables like $site,$containingfolder, etc if(isset($_FILES['uploadedfile']['tmp_name'])){ $url = $site.$containingfolder.$_FILES['uploadedfile']['tmp_name']; }elseif(isset($_POST['url'])){ $url = $_POST['url']; }else{ die(); } //Code continues to insert to DB [/CODE] check out [URL="http://www.tizag.com/phpT/fileupload.php"]this tutorial[/URL] as to …

Tell me wether this gets you theoutput you need [CODE] //this will independently echo every raw input. foreach($raw as $val){ echo $val; } //you can just implode your raw data to a final variable. $final = implode(",",$raw); [/CODE]