soroushc

Hi:)the problem im facing is that i created a control Textfield.Example :the user types in 75000 in the textfield and after he or she presses enter the List view appears. But i want them to hit a button so after hitting the button the list view appears?plz help

It's my assignment I have done almost I have completed it.But I have problem in getting input from user(the bank name)here is my assignment question. Customer often wait in the bank..!you have to ask the user the entire as many bank names as he desires and time (waiting time the …

hi,I know that your code has been solved!But I didn't see the solution!But I have fixed by initializing start and end giving them size 0!It runs now!is it correct or not? [ICODE]#include <conio.h> #include <iostream> using namespace std; int main(){ int start = 0,end = 0; double a[start-end][2],p[start-end]; cout<<"Enter a …

how to get a string using array? and how can I get input in this format string|12.3 12.23 | example;with no space between the lines and when user enter 0 it will exit david|12.3 24.2| Peter|12.4 24.2|

now it opens a file! do u mean also that after opening a file it must ask the user for another input? [ICODE]#include<iostream> #include<fstream> using namespace std; int main() { string FileName; char tryAgain = 'y'; ofstream inFile; //create open type ! while (tolower(tryAgain) == 'y') { cout << "Please …

The calculation is wrong! think about ASCII CODE;) [ICODE]#include<iostream> using namespace std; int main() { int val=0,n=0; double ave; long sum=0; cout<<"please enter the first interger..."<<endl; do { cin>>val; if(!cin) { cin.clear(); cin.ignore(100); } else { sum+= val; ++n; cout<<"please enter another interger..."<<endl; cout<<"sum is in loop: "<<sum<<endl; } }while(cin>>val); …

don't type else part of if statements!just write two if statements!this would save you some time when you want to later view the program!

HELLO EVERYONEE!I Love programingg!It's a great fun!:) I know how to write program's in C++ and I'm learning Visual C # by my ownself!:) would be glad to meet other programmers:)