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how to pass the value 'id_category' from this page list.php [code] <title>home</title> <!--for auto refresh--> <META HTTP-EQUIV=Refresh CONTENT="300; URL=http://localhost/recipe2/home.php"> <body> <div align="left"><img src="Cookie Banner edited.jpg" width="1100" height="200" /></div> <h2>My Account </h2> <p>chef today : <?php echo $_SESSION['myusername']; ?> | <a href="logout.php">Logout</a> </p> <p> </p> <p> </p> <?php include 'recipe2db.php'; $sql="SELECT id_category FROM …
after login, go to this page. client will click those button then view each recipe they click. list.php [code] <?php session_start(); if(!isset($_SESSION['myusername'])&&!isset($_SESSION['mypassword'])) { header('Location:401.php'); } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <!--for auto refresh--> <META HTTP-EQUIV=Refresh CONTENT="300; URL=http://localhost/recipe2/home.php"> <title>home</title> </head> <body> <div align="left"><img src="Cookie …
update.php [code] <?php include 'recipe2db.php'; // get value of id that sent from address bar $id=$_GET['id']; // Retrieve data from database $sql="SELECT * FROM recipe WHERE id='$id'"; $result=mysql_query($sql); $rows=mysql_fetch_array ($result); ?> <form name="form1" method="post" action="update_ac.php"> <table border="1" cellspacing="0" cellpadding="3"> <thead> <th>name</th> <th>ingredient</th> <th>how to cook</th> <th>category</th> </thead> <tr> <td> <input …
i delete a row of data from this [code] ........ <a href="delete.php?id=<? echo $rows['id']; ?>">delete</a> [/code] delete.php [code] <html> <body> <?php include 'recipe2db.php'; // get value of id that sent from address bar $id=$_POST['id']; // Delete data in mysql from row that has this id $sql="delete from recipe where `id` …
add.php [code] <?php include 'recipe2db.php' ?> <div align="left"><img src="Cookie Banner edited.jpg" width="1100" height="200" /> <form name="form7" method="post" action="add_process.php"> </p> <p> </p> <table align="center" border="3" cellpadding="2" cellspacing="2"> <tr> <td>catagory :</td> <td> <?php include 'recipe2db.php'; $query="SELECT id_category, category_name FROM category"; $result = mysql_query ($query); echo "<select name=category value=''></option>"; // printing the list box …
how to create an application for client and server through any port available using Red Hat Linux.. give some link to refer...
we need to link this interface to database.. but i fail to connect this.. [code]<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> <title>Untitled Document</title> </head> <body> <form id="form1" name="form1" method="post" action=""> <p><img src="header2.jpg" alt="header" width="800" height="100" /></p> <blockquote> <p align="left"><strong>Friends</strong>List</p> <p> <textarea …
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