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Member Avatar for itsrahulk

From a quick look I got on your post, your [B]Ajax.Updater syntax[/B] is totally wrong. You need to supply a DOM element as an argument, or in plain english, you must say to Ajax.Updater [B]where[/B] you want it to display the results of 'sample.php' (in other words, the place where …

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The End.