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Re: hcf and lcm
[QUOTE=mitrmkar;592469]Umm, I think I got the hcf part of it (thanks hammerhead), but how to figure out 'lcm of 2 nos' just beats me :-/ ...[/QUOTE] lcm is the easy part theres a property in maths: for to number x and y hcf(x,y) * lcm(x,y) = x*y just divide the …
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