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How would I go about getting a variable from a jQuery plugin? index page [CODE] $("#test-div").myplugin(); if(testvariable == 1){ alert("test variable equals 1"); } [/CODE] The plugin page [CODE] (function($){ $.fn.myplugin = function(){ var testvariable=1; return testvariable } })(jQuery); [/CODE]
I just would like to know how to do this? Just like facebook! Lorem ipsum dolor sit amet, consectetur adipiscing elit. Nam fermentum posuere arcu lobortis mattis. In eu nisl turpis. Praesent mi dui, dignissim et rhoncus nec, sodales vel sapien. In hac habitasse platea dictumst. Etiam quis felis vitae …
Here you go: [URL="http://www.rrpowered.com/tuts/2010/03/pretty-urls/"]http://www.rrpowered.com/tuts/2010/03/pretty-urls/[/URL]
[CODE] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>Items</title> <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.4/jquery.min.js"></script> <script type="text/javascript"> //When dom is ready $(document).ready(function(){ //onChange function $("#dropdown").change(function() { //Get th selected option text or to get value use //var items=$("#dropdown option:selected").val(); var option=$("#dropdown option:selected").text(); //Get each option $("#dropdown option").each(function(){ //Get each …
Is there a way of checking if a YouTube user exists?
[CODE]<?PHP $results = mysql_query("SELECT * FROM messages, comments WHERE messages.user_on='$user2' AND comments.msg_id_fk = messages.msg_id ORDER BY messages.msg_id, comments.com_id DESC") or die(mysql_error()); ?>[/CODE]
[CODE]<?PHP $results = mysql_query("SELECT * FROM messages, comments WHERE messages.user_on='$user2' AND comments.msg_id_fk = messages.msg_id ORDER BY messages.msg_id, comments.com_id DESC") or die(mysql_error()); ?>[/CODE]
Display Div tags after 4 results not from database [CODE] $a = 0; while(){ if($a == 4){<div class="result"><p>}//Display after 4 results $results .=''.$result.''; if($a == 4){</p></div>}//Display after 4 results $a++; } example: <div class="result"><p> result 1 result 2 result 3 result 4 </p></div> <div class="result"><p> result 5 result 6 result …
I need to display all the comments from the comments database table where the $msg_id_fk = $msg_id from the messages table and I need it in a while loop [CODE] $comment_results = mysql_query("SELECT * FROM comments WHERE msg_id_fk='$msg_id' ORDER BY com_id ASC"); while ($row = mysql_fetch_array($comment_results)){ $msg_id_fk=$row['msg_id_fk']; $comment=$row['comment']; } $message_results …
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