sakthi@daniweb

[code=c] #include<stdio.h> #define scanf "%s is char" main() { printf(scanf,scanf); } [/code] the output is %s is char is char y it is so..

i will try .i will say within 24 hours. according to me the logic is as follows.. using 1 loop for printing ab abcd and using another loop for printing a aei aeiou this can be achieved through boolean value conditions in java and an other idea is to use …

this is the coding of 4cups(paper fold game) game that we played in schoolings... [code=c] #include<stdio.h> #include<conio.h> void even(); void odd(); void cal1(); void cal2(); void job(); char z[]="one",y[]="two",x[]="three",w[]="four",v[]="five",u[]="six",t[]="seven",s[]="eight"; void main() { char a[10],b[]="red",c[]="green",d[]="blue",e[]="yellow"; clrscr(); printf("enter your favourite color from given choice:\n"); printf("red\nblue\ngreen\nyellow\n"); scanf("%s",&a); if(strcmp(a,b)==0||strcmp(a,c)==0) { printf("good luck .you have …

you can use turing machine concept than finite machines to this..

[code=c] #include<stdio.h> main() { int a=5; printf("%d,%d%,d",++a,++a,++a); } [/code] the output of this is 8,7,6 instead of 6,7,8 y it is so...

this is the coding of 4cups(paper fold game) game that we played in schoolings... [code=c] #include<stdio.h> #include<conio.h> void even(); void odd(); void cal1(); void cal2(); void job(); char z[]="one",y[]="two",x[]="three",w[]="four",v[]="five",u[]="six",t[]="seven",s[]="eight"; void main() { char a[10],b[]="red",c[]="green",d[]="blue",e[]="yellow"; clrscr(); printf("enter your favourite color from given choice:\n"); printf("red\nblue\ngreen\nyellow\n"); scanf("%s",&a); if(strcmp(a,b)==0||strcmp(a,c)==0) { printf("good luck .you have …