Brianbc

See here: $row = mysqli_fetch_array($myquery, MYSQLI_ASSOC); ?> <div id="pdata" class="printArea"> You are only accessing one row from the result of your query. And that is all that there will be in pdata. So maybe you should modify to have a loop like this`while($row = mysqli_fetch_array($myquery, MYSQLI_ASSOC)){}` Then put pdata before …

The method you form uses to send data to the server is POST. So on line 28 use POST as opposed to the GET you've used.

Why wouldn't you want to make good use of jquery. [url]http://code.jquery.com/jquery-1.7.js[/url]

[CODE]<?php /* +-----------------+------------------------------------------------------------+ | Class | setup | | Author | Brian Onang'o | | Version | 1.0 | | Last Modified | 10:16 AM 10/2/2010 GMT+3 | +-----------------+------------------------------------------------------------+ | This program is free software; you can redistribute it and/or | | modify it under the terms of the GNU …

I need some help with inheritance in php. The code below does not produce any output. [CODE] Class Father{ var $car; Function inherited(){ print $this->car; } } Class Son Extends Father{ Function __Construct(){ $this->car='Benz';//I'm assuming here that car is still a property of father. } } $obj= new Father; $obj1= …

Working with some OOP, I had an error that I have now traced to inistantiation of a class when the file in which the class is contained is included in any other file. Is this the default/normal behaviour of php, and how do I get myself out of this? I …

This Christmas day, I am plagued by this negative nibble mystery. I have some bytes in a byte array that I want to split into nibbles [CODE] x = bytes(n) x = x << 28'cause the left 4 bits to overflow so we remain with only the right 4 bits …

I have been searching for a single line of code all evening, and I think it's only prudent that I seek help. What line of code does the opposite if this? [CODE]WebBrowser1.Document.GetElementById("username").SetAttribute("Value", "username")[/CODE] I want to read some data from a php form and assign it to a string.

[CODE]'<form action="" method="post"> '<fieldset> ' <ul> ' <li> ' <input type="text" name="username" id="user"/> ' </li> ' <li> ' <input type="password" name="pass" id="pass"/> ' </li> ' <li> ' <input type="submit" name="submit" value="submit"/> ' </li> ' </ul> '</fieldset> '</form>[/CODE] Above is a php form that has refused to be submitted by my …

I have a file(File1) in the root directory(Root). There is also a directory(Dir) in the root directory which contains File2. File2.php [CODE]<?php include'/*I need to include file1 here*/' // ?>[/CODE] How do I include file1 in file2?

I have a personalised webbrowser in VB 2005. It fills values into a form and submits the form. The first page is "login.php", the next page is "home.php" [CODE] SendKeys.SendWait("{TAB}") SendKeys.SendWait("{TAB}") SendKeys.SendWait("username") SendKeys.SendWait("{TAB}") SendKeys.SendWait("password") SendKeys.SendWait("{Enter}")[/CODE] I want it to do something else based on the url after the form is …

I am loading a page to change passwords within an iframe. Outside the iframe it does work well, but when I change the password from within the iframe it returns a blank page. How can I rectify the problem? [CODE]//iframe <div class="tabber"> <div class="tabbertab"> <h2>Eguard</h2> <iframe src="eguard.php" width="100%" height="400"> </iframe>[/CODE]

I am using the code below to insert time into a table, and this is the output it's giving me: 0000-00-00 [CODE]//table start DATETIME, //code to insert date into db $_POST['start']=date("Y-m-d H:i:s"); $insert = "INSERT INTO eguardIPs (Field1,Field2,Field3,start) VALUES ('".$_POST['Field1']."', '".$_POST['Field2']."', '".$_POST['Field3']."', '".$_POST['start']."')"; $add_start = mysql_query($insert);[/CODE]

My file below checks if the user is ! logged in, and redirects to login page, or does nothing if user is logged in. [CODE]<?php if(isset($_COOKIE['SID'])) { $sid= $_COOKIE['SID']; $uid = $_COOKIE['User']; $lastip = $_COOKIE['Cname']; $_POST['SID']=$sid; $check = mysql_query("SELECT * FROM users WHERE SID = '".$_POST['SID']."'")or die(mysql_error()); while($info = mysql_fetch_array( …

Thanks kasim.badami. I had also been strugling with the same problem the entire day till I realised this(') was missing!