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Anyone can help me with this algorithm? 1 set up stack in and print it 2 while stack in is not empty repeat 2.1 max = in.pop 2.2 while there are still element in stack in repeat 2.2.1 value = in.pop 2.2.2 if value > max 2.2.2.1 temp.push(max) 2.2.2.2 max …
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