hr.Ziggurat

which data are taken from table in while loop? u don't use from '$fetch'. and you need only to have review field (every movie title there is only one time ). therefore while loop not necessary. u did not explain source and rating. but i think this will help u: …

it's really easy! function vali_pattern(text){ if(text.length==6) if(text.charAt(0)<='Z' && text.charAt(0)>='A') if(text.charAt(1)<='Z' && text.charAt(1)>='A') if(text.charAt(2)<='Z' && text.charAt(2)>='A') if(text.charAt(3)<='9' && text.charAt(3)>='0') if(text.charAt(4)<='9' && text.charAt(4)>='0') if(text.charAt(5)<='9' && text.charAt(5)>='0') return true; return false; }

where is your problem? give more explanation.

its better to use from a php IDE to ensure typing. u did some typing error. and the input tag name (file type) must end with [] , to access to the each uploaded file , u must give the file index number to the $_FILES array , then its …

try this : [Click Here](http://www.uploadmb.com/dw.php?id=1345588204) sorry if that was not useful. please give me more information if your problem not solved. Amo l'Italia! viva l'Italia!

u cant write a javascript code in php tag. for do this , use from echo. <?php echo "if(document.getElementById('month').value < $month){"; echo "alert('That month has already passed! Please put a valid month.');}"; ?> getElementById('month') returns a object but you need its value.

empty space not related to loading effect and is result of your css and html codes , but perhaps u write middle things into a div tag with loading id. in this case , u shuold change #loading style and remove 'line-height: 350px;' or decrease its value.( hamkeshavari! )

use from json_encode to convert each character to a hex code word. ie: <script type="text/javascript"> <?php $f = json_encode("a utf-8 text"); $f = str_replace("\\","%",$f); $f = str_replace("\"","",$f); echo "alert(unescape(\"$f\"))"; // convert to normal characters ?> </script>

Hi. i'm trying to login to an asp login page via php and curl... i wrote this code by google help. i expect see originale login page whith invalid username and password message , but i see only 'Object moved to here.' error. <?php $urlLogin = "http://xxxx/LoginPage.aspx"; $nameUsername='txtUsername'; $namePassword='txtPassword'; $valUsername …