4 Posted Topics
Try replacing your code with the following. If it works, tell me and I'll explain why. $qry = mysql_query('INSERT INTO `postjob` (jobtitle, positions, category) VALUES ("'.$_POST['title'].'", "'.$_POST['position'].'", "'.$_POST['cate'].'")'); if(!$qry) { die(mysql_error()); }
Not sure why everybody is making this so complicated, it's simple. IF I have a table called "records" and the first column is called "id" (as should be on every databse table), then I'd grab the ID from each row (fastest mysql query possible, since it's a small result) and …
Two methods come to mind: 1. Use a cookie to track the login, and give it an expiry time of 15 minutes from creation. Every time they load another page, or reload the current page, you check for a cookie and if they're logged in you renew the expiry time. …
We're not a coding service, but you can always try freelancer.com if you want to pay somebody a small amount (or me).
The End.
yehuda2001