linus72982

Makeitonline, I believe you need a semicolon after $date inside the php tags. All other stuff being correct, it should work after that.

If the code inside the while loops isn't running, it's probably because p is not less than tangerine. Have you checked the values against each other? For example, what is tangerine equal to in a test scenario?

Need a bit more info. What do you mean by articles? Are you saying you have a database with newspaper articles that you're trying to pull or are you using articles as a synonym for fields or rows in the database (as in "article of clothing")?

I have a layout for an app that has a panel that places 3 static boxes (nodes) per row, and then keeps going until the dictionary of nodes is out. I figured out the flex grid sizer to do so (wrapped by regular boxsizers to add padding above and on …

Well, you haven't told us what you are getting so it's hard to pinpoint a problem. Is it a blank screen? Are you not getting the correct database results? Are the forms not showing up correctly? A few notes from a quick glance-over: - Not sure if this is still …

Could you give some more information? Post the code you have for the forms and I can guide you through writing a script to email it to you.

I'm not going to try and sort through all that, but let's see if I can give a more abstract answer that points you in the correct direction. If I understand your question correctly, you want to display rows based on some condition? You have a few choices. The best …

No, you need parentheses around the condition check, like this: `if ($password == $result) {` Also, I'm not too skilled at security, but I think you're going to want a check to make sure that the POST vars came from your page -- you can do this by adding a …

You're not actually making a call to the database. If I remember correctly, for mysqli it's something like $connectionVar->query("query string") or something similar. Currently, you're just storing a string in the mysqli var and the results var but no action is occuring. EDIT for clarity: If my mysqli knowledge is …

I just did a quick once-over, but here's what I saw: You are checking to make sure $_POST['submit'] is equal to true to start processing. Try adding a name and value to the input: `<input type="image" src="images/login.jpg" alt="submit" width="200px" name="submitButton" value="login">` and then check for that name and value to …