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Maby an other short method with the help of List Comprehensions: (very fast) [ICODE][[id,name]for id in range(2)for name in range(3)][/ICODE] Result: [[0, 0], [0, 1], [0, 2], [0, 3], [1, 0], [1, 1], [1, 2], [1, 3], [2, 0], [2, 1], [2, 2], [2, 3]] ore in this way [ICODE][[[id]for …
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