-ordi-

[QUOTE=LoveMyPadres;1464044][CODE] import os base = 'f4761' Series = ['sk','se','pl','no','nl','ie','hu','gb','fi'] for series in Series: for xx in reversed(range(1,4)): file = base+series+str(xx).strip()+".py" os.system( file ) [/CODE] Python is always the right answer.[/QUOTE] Don't use "file" as variable name, use something other (ffile etc).

[CODE]# -*- coding: utf-8 -*- from PyQt4 import QtGui from PyQt4.QtCore import * import sys import os class VideosToMp3(QtGui.QWidget): def __init__(self, parent = None): super(VideosToMp3, self).__init__(parent) ''' Labels and GUI ''' extension = QtGui.QWidget() download_label = QtGui.QLabel("Enter YouTube video URL:") self.download_line_edit = QtGui.QLineEdit() file_label = QtGui.QLabel("Enter file name (optional):") self.file_line_edit …

[CODE]import yaml file = open('file.yaml', 'r') d_yaml = yaml.load(file.read()) file.close for _data in d_yaml: a = [variable['text'] for variable in _data['text']] i = _data['info'][0]['info'] p = _data['info_o'][0]['info_o'] print str(a) + '\n' print str(i) + '\n' print str(p)[/CODE] [CODE]- name: name1 text: - text: aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa - text: bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb info: - info: …

[CODE]from heapq import heappush, heappop import random import time def print_timing(func): def wrapper(*arg): t1 = time.clock() res = func(*arg) t2 = time.clock() print '%s took %0.3fms' % (func.func_name, (t2-t1)*1000.0) return res return wrapper h = [] @print_timing def heapsort(N): for i in range(0, N): heappush(h, random.randint(0, N - 1)) return …

[CODE]mylist = [['fiss','giss'], ['e','h'], ['d','u'], ['c','t'], ['b','o'], ['a','z']] g = '' for alist in mylist: g += ' '.join(alist) print g f = open("write.txt", "w") f.write(g) f.close()[/CODE] g = '' # It's empty string in for loop ... g = something # It's replaced at every time g += 'sometext' …

[CODE]public class Algarv { public static void main(String args[]) { int numbrid = 0; // Proovime kohe algusest int loendur = 0; // Loendame üles, et pärast lihtsam oleks while(loendur < 100) // Eelkontrolliga, t2idame kuni see on 100 { numbrid++; if(numbrid % 2 != 0) { int abi = …

[CODE]prime_count = prime_count + 1 [/CODE] and same [CODE]prime_count += 1[/CODE]

Dynamic programming is good to solve that problem (better than recursive). [CODE]table[0] = 1 table[1] = 2 table[i] = table[i - 2] + table[i - 1][/CODE]

[CODE]tabwidget = QtGui.QTabWidget() widget = QtGui.QWidget() layout = QtGui.QGridLayout(widget) tabwidget.addTab(widget, QString.fromUtf8("New Tab"))[/CODE]

[CODE]list = [1, 2, 3, 4] index[0] = 1 index[1] = 2 index[2] = 3 index[3] = 4 l.pop(0) --> 1 l.pop() --> 4 new list ==> [2, 3] index 0 --> 2 index 1 --> 3 l.pop(1) --> 3[/CODE]

Maybe [CODE]python file.py[/CODE] Sorry I'm using Linux and i don't now how it works in Windows. [url]http://docs.python.org/faq/windows.html[/url]

Firstly don't use variable names as file/list etc or something like that, use ifile/afile or ... initial.txt is not variable -> it is file name, use "example.txt" --> " " or ' ' [CODE]filename = "initialpositions.txt"[/CODE] To write this to file: [CODE]val.write("\n".join(str(elem) for elem in initial))[/CODE] [CODE][ 745. 1306. 630.] …

Hei, youre code identitation is not correct.

Better Gnome sort: [CODE]def gnomesort(seq): i = 0 while i < len(seq): if i == 0 or seq[i-1] <= seq[i]: i += 1 else: seq[i], seq[i-1] = seq[i-1], seq[i] i -= 1 [/CODE]

[CODE]if 2 == 3: return True else return False[/CODE] [CODE]len(primes) = 1 but list index start at 0 --> primes[len(primes) - 1]:[/CODE] [CODE]list.append(element)[/CODE]

Is it graph exercise?

[CODE]class Fraction: def __init__(self): pass def gcd(self, n, m): while m % n != 0: m, n = n, m % n return n n = Fraction() print n.gcd(6, 3) from fractions import gcd print gcd(6, 3)[/CODE]

Hei, I tried to find "dynamic programming" algorithms in Python. If anyone has examples of what it means a dynamic programming, it's would be nice. (Please not post Wikipedia links). Google -> c++, java and other, not Python. Thanks!

Use YAML or JSON.

[CODE]while name == 'Name'[/CODE]

Maybe beter? [CODE]for i in range(len(dict_file)): #dict_file[i] = dict_file[i][0:len(dict_file[i])-2] #eliminate \n, line characters in the dictionary dict_file[i] = dict_file[i].strip()[/CODE] [CODE]list_words = input_text.strip().split(' ')[/CODE] [CODE]Unknown words are: () (1, '\t', 'general-purpose') (2, '\t', 'high-level')[/CODE] Python 2.5 Linux

[CODE]line = "a1 a2 a3 a4 a5 a6".split() print line[0], line[3][/CODE] [CODE]with open ("test.txt") as sis: for line in sis: split_line = line.strip().split() print "%s %s" % (split_line[0], split_line[3]) sis.close() """ a1 a4 b1 b4 c1 c4 d1 d4 """[/CODE] Here: [url]http://docs.python.org/[/url] try to learn Python.

[CODE]from copy import deepcopy sis = file("teedtest.01.sis", "r") val = file("rp.val", "wt") N, K = map(int, sis.readline().strip().split()) alist = [] for i in range(0, K): t = [] for i in range(0, K): t.append(0) alist.append(t) for i in range(K): a, b, c = map(int, sis.readline().strip().split()) alist[a][b] = alist[b][a] = c …

[CODE]#include <stdint.h>[/CODE] [CODE]int pow(uint64_t b) { int j = 2; // n ^ m, n ^ m + 1 ... n ^ (m - 2) for (int i = 2; i < b; i++) { j += j; } return j; }[/CODE] [CODE]int main() { int a, b; for (int …

[CODE]l = [1,5,9,11,13,21,27,29,32] num = 15 for index in range(len(l) - 1): if (num > l[index]) and (num < l[index + 1]): print index, l[index], l[index + 1][/CODE] or use (len(l) - 1)

You need [url]http://docs.python.org/library/subprocess.html[/url] ?

[CODE]sis = file("file.sis", "r") val = file("file.val", "wt") n = int(sis.readline().strip()) la = sis.readline().strip() alist = [] for i in xrange(n): line = sis.readline().strip() alist.append(line.split()) for i in xrange(n): print map(int, alist[i][0].split(":")), map(int, alist[i][1].split(":")) [/CODE] In: [CODE] 07:34 08:55 10 20 08:25 09:00 10 20 [/CODE] Out: [CODE] 08:25 09:00 …

Try regular expression: [url]http://diveintopython.org/regular_expressions/index.html[/url] Bad example: [CODE] import re infile = open("test.txt","r") outfile = open('out.txt', 'w') while True: text = infile.readline().strip() if text: nr = re.findall('[0-9.]+', text) print nr[1:] continue else: break infile.close()[/CODE]

Ok maybe this code helps you: [url]http://v6sa.itcollege.ee/shared/ITK/Lineaar/det.py[/url]

[CODE]#include <iomanip> #include <iostream> #include <fstream> #include <string> using namespace std; struct Student { string name; }; void printNames(Student* student, int nStudents) { int i; for (i = 0; i < nStudents; i++) { cout << student[i].name << endl; } } int main() { ifstream fin; // opening file string …

Input: A, B, C, D, E ... [CODE] 1/1 1/2 2/3 3/4 2/5 [/CODE] Output (Queue!): [CODE] 5 B 1 E 3 C 4 D 2 A [/CODE] How to make this? Mark competitors (persons) Example: A ... E their come in first queue. A can label/tag 1/1. B can …

[url]http://stackoverflow.com/questions/493174/is-there-a-way-to-convert-number-words-to-integers-python[/url]

[CODE]protein = max(dict.values(), key=int) print protein[/CODE] and [CODE]proteins = max(dict.iteritems(), key = lambda x:int(x[1]))[0][/CODE]

[CODE]f = open("summatest.01.sis", "rt") n = (f.readline()) jada_elemendid = f.readline().strip().split(' ') otstav_summa = f.readline().strip() f.close() # Valjund vfal = file("sum.val", "w") lmargid = [] def otsi(k): if (k < n): print n k = k + 1 lmargid.append("+") if otsi(k): return True lmargid.append("-") print lmargid else: z = jada_elemendid[0] for …

Best way to parse this webpage private info: [url]https://ee.ekool.eu/index_et.html?r=2#/?screenId=g.user.login&err=1[/url] I found Beautiful soap and PyKhtml. What is the better?

Hei, I have planned make Tv-Browser and using Qt, C++ or Python. And Linux of course :)

Please post your code.

[CODE]def triangle(): totalRows = int(input("Please enter a number: ")) for totalRow in range(1, totalRows + 1): print '*' * (totalRow) triangle()[/CODE] Something like that?

[CODE]print divmod(1024, 26) # 39[/CODE] [CODE]print chr(39 + ord('A') - 1) # g[/CODE] but: AA, AB etc, how to convert this to number?

Hei, [CODE]list = [line.split() for line in open(file) if line is not None][/CODE] and output: [CODE][linux@localhost ~]$ [[], ['text'], ['text', 'text', 'text', 'text'], ['text', 'text', 'text', 'text']][/CODE] How to remove none types [] or something.

If you are using Gnome -> use wxpython. If you are using KDE -> use Qt4.

Use Qt Creator. [url]http://qt.nokia.com/products/developer-tools/[/url]

[QUOTE=caut_baia;1297427]Here's a start .. [code] #include <vector> #include <iostream> #include <string> class Person { std::string Name; std::string Adress; public: Person() {} Person (std::string n,std::string a) : Name(n) , Adress(a) {} virtual void Display() { std::cout << "Name: " << Name << "\tAdress: " << Adress; } virtual ~Person() {} }; …

Small example (Qt Python program): [CODE]# -*- coding: utf-8 -*- import sys #Import the PyQt4 modules. Exit if not found. try: from PyQt4.Qt import * from PyQt4.QtCore import * from PyQt4.QtGui import * except: print "Failed to load QT libraries. Please intall PyQt4 first." sys.exit(1) class Calculate(QMainWindow): def __init__(self): QMainWindow.__init__(self) …

[QUOTE=linuxoidoz;1287091]Oh, I know this, just forgot about it. Now it makes sense. The escape thing doesn't work either. If not even unicode shows it, then I don't know what will. So, there's no other way to show a '&'?[/QUOTE] Try this: [CODE] self.b1 = QPushButton("&&Hello", self)[/CODE] Simple Qt code: [CODE]# …

Maybe: [CODE] for a in range(20): print "*" * 10[/CODE] Multiplication table: [CODE] i = 0 while i <= 10: j = 0 while j <= 10: print ("%4d" % (i * j)), j += 1 print i += 1[/CODE]

[CODE]self.connect(self.youre_ui.youre_push_Button, QtCore.SIGNAL('clicked()'), QtGui.qApp, QtCore.SLOT('quit()'))[/CODE] or [CODE]self.connect(self.ui.youre_push_Button, QtCore.SIGNAL('clicked()'), self.youre_function)[/CODE]

How to open default text editor? Using Linux and Python 2.6

[CODE]def binary_search(a, n, required): start = 0 end = n - 1 answer = 0 while start <= end: middle = (end + start) / 2 if a[middle] == required: answer = middle break else: if required < a[middle]: end = middle - 1 else: start = middle + 1 …

[url]http://docs.python.org/[/url]